A right-angled triangle with base 15 cm and height 50 cm is rotated along its base to form a cone. determine the approximate volume of the cone so formed. (rounded off to nearest integer)
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We know the formula of volume of cone=1/3*(pi)*r^2h.
When the right-angled triangle is rotated along its base,
The base of right-angle triangle would be transformed into height of the cone. And height of the triangle would be equal to the radius of the cone.
Thus,
The volume of the cone would be=1/3*(pi)*r^2*h where r=50 cm and h=15 cm
=(1/3)*22/7*50^2*15
=(1/3)*22/7*50*50*15
=39286 (approx)
Therefore, the volume of the cone would be 39286cm^3 approximately.
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