A right angles triangle has the largest side as 13 cm and one of the sides containing the right angle as 12 cm.Its area in cm square is
Answers
Answered by
3
Largest side = Hypotenuse = 13 cm
Base = 12 cm
Perpendicular = sqrt (H^2 - B^2)
= sqrt (13^2-12^2)
= sqrt (169-144)
= sqrt 25
= 5 cm
Perpendicular = 5 cm
Area = Base *Perpendicular / 2
= 5 * 12 / 2
= 5 * 6
= 30 cm^2
Base = 12 cm
Perpendicular = sqrt (H^2 - B^2)
= sqrt (13^2-12^2)
= sqrt (169-144)
= sqrt 25
= 5 cm
Perpendicular = 5 cm
Area = Base *Perpendicular / 2
= 5 * 12 / 2
= 5 * 6
= 30 cm^2
Answered by
0
Hypotenuse = 13 cm
Base = 12 cm
Perpendicular =?
P = ✔ H^-B^ (✔ = sq. root)
( ^= 2 or sq.)
P= ✔️169-144
P= ✔ 25
P= 5 cm
Area of right triangle = 1/2×b×h
Area = 1/2×12×5
Area=30cm sq.
Base = 12 cm
Perpendicular =?
P = ✔ H^-B^ (✔ = sq. root)
( ^= 2 or sq.)
P= ✔️169-144
P= ✔ 25
P= 5 cm
Area of right triangle = 1/2×b×h
Area = 1/2×12×5
Area=30cm sq.
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