A right circular cone is 3.6 cm high and radius of its base is 1.6 cm.it is melted and recast into a right circular cone with radius of its base as 1.2 cm.find the height
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For cone, h = 3.6 cm, r = 1.6 cm
Volume of the given cone = 1/3 Π r2 h = (1/3 x 22/7 x 1.6 x 1.6 x 3.6) cm3
Radius of the second cone = 1.2 cm. Let its height be h1, then
Volume of the second cone = 1/3 Π r2 h = 1/3 x 22/7 x 1.2 x 1.2 x h1
Since the volume of the cones would be equal, so
1/3 x 22/7 x 1.2 x 1.2 x h1 = 1/3 x 22/7 x 1.6 x 1.6 x 3.6
=> h1 = (1.6 x 1.6 x 3.6) / (1.2 x 1.2) = 6.4
Hence, the height of the second cone is 6.4 cm
Volume of the given cone = 1/3 Π r2 h = (1/3 x 22/7 x 1.6 x 1.6 x 3.6) cm3
Radius of the second cone = 1.2 cm. Let its height be h1, then
Volume of the second cone = 1/3 Π r2 h = 1/3 x 22/7 x 1.2 x 1.2 x h1
Since the volume of the cones would be equal, so
1/3 x 22/7 x 1.2 x 1.2 x h1 = 1/3 x 22/7 x 1.6 x 1.6 x 3.6
=> h1 = (1.6 x 1.6 x 3.6) / (1.2 x 1.2) = 6.4
Hence, the height of the second cone is 6.4 cm
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