Let p and q be two real numbers with p greater than o. Show that the cubic X3 +px+q has exactly one real root.
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We will Let f(x) = x³ + px + q
f'(x) = 3x²+p which is greater than zero.
We can conclude form this that f is the increasing function here.
x tends to minus infinity f(x) = - infinity
x tends to infinity f(x)= infinity
So we can say that there is only 1 real root.
If there is any confusion please leave a comment below.
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