A right circular cone, of height 12 ft, stands on its base which has diameter 8 ft. The tip of the cone is cut off with a plane which is parallel to the base and 9 ft from the base. With π = 22/7, the volume, in cubic ft, of the remaining part of the cone is
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Answer:
Given that the diameter of base = 8 ft
Therefore, radius of circular base = 8/2 = 4 ft
Explanation:
In triangle OAB and OCD
OA/AB = OC/CD
⇒ AB = (3 × 4)/12 = 1 ft
Volume of cone = 1/3 × π × r2 × h
Volume of remaining part = Volume of entire cone - Volume of smaller cone
= 1/3 × π × 42 × 12 - 1/3 × π × 12 × 3
= 1/3 × π × 189
= 198 cubic ft
The correct answer is 198.
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Explanation:
The correct answer is 198.
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