Math, asked by pksda5848, 1 year ago

A right circular cone of height 30 cm. A small cone is cut off from the top by a plane parallel to the base. If the volume of small cone is 1/27 of volume of given cone, find at what height above the base is the section made

Answers

Answered by Anonymous
2

Answer:

Step-by-step explanation:

Given: A right circular cone of

height 30 cm

It is cut off from the top by a plane parallel to the base

Volume of the small cone = 1/27 of volume given cone

Solution:

t the height and radius of original(big) cone be H and R

let the height and radius of cut off (small) cone be h and r

from congruent triangles, we know  

H / R = h / r

h = H r / R

since H = 30

h = 30 (r /R) .......................................................(1)

Volume of big cone, V = (1/3) pi R2 H

volume of small cone,v = (1/3) pi r2 h

now dividing , we get  

V / v = (R2 H )/ (r2 h) = 27 (since volume of small cone is 1/27 of big cone)

=> R2 H = 27r2 h  

=> 30 R2 = 27r2h                     { since the H = 30 cm given }

=> h = (30R2) / ( 27 r2 )

=> h = (30 /27)(R /r)2 .................................................(2)

   From equating (1) and (2)

=> 30 (r /R) = (30 /27) (R/r)2

=>(r /R)3 = 1 / 27

=> r / R = 1/3........................................................(3)

substituting eq (3) in eq (1), we get

=> h = 30 (r /R)

=> h = 30 (1/3) = 10 cm

The section is made above the base is 30cm - 10cm = 20 cm

Answered by singhdipanshu2707200
0

Answer:

Check your answer please

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