A right corcular cylindrical tunnel of diameter 23m and length 40m is to be constructed from a sheet of iron. The area of iron sheet required is?
Answers
Answered by
0
Hi there !!
Diameter = 23 m
Radius = r = 23/2 m
Length = Height = h = 40 m
Area of iron sheet required is = C.S.A of the cylindrical tunnel = 2πrh
= 2 × 22/7 × 23/2 × 40
= 2891.42 m² [ approx.]
Diameter = 23 m
Radius = r = 23/2 m
Length = Height = h = 40 m
Area of iron sheet required is = C.S.A of the cylindrical tunnel = 2πrh
= 2 × 22/7 × 23/2 × 40
= 2891.42 m² [ approx.]
Answered by
0
r= 23/2 m
h = 40 m
Area of iron sheet required = C.S.A of the cylindrical tunnel = 2πrh
= 2 × 22/7 × 23/2 × 40
= 2891.42 m²
Similar questions
English,
8 months ago