Question

a right triangle ABC circumscribes a circle of radius R if a b and b c are of length 8 cm and 6 CM respectively find the value of R

Answer 1

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Answer 2

Answer:

Step-by-step explanation:

AB, BC and CA are tangents to the circle at P, N and M.

∴ OP = ON = OM = r (radius of the circle)

By Pythagoras theorem,

CA2 = AB2 + BC2

⇒ 10 = AB2 + 62

⇒ AB2 = 64

⇒ AB = 8 cm

Area of ∆ABC = Area ∆OAB + Area ∆OBC + Area ∆OCA

24= 1/2rAB +BC+ CA)

24=1/2r(24)

r=24*2/24

r=2

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