a right triangle ABC with sides 5 cm 12 cm and 13 cm is revolved about the side 12 cm find the volume of the solid
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Answered by
15
when it will be revolved around side 12 cm then it will become a cone of height 12 cm and radius 5 cm
volume of cone = 1/3π r^2h
=1/3 * 22/7 * 5*5*12
=100*22/7
=314.28cm^2
volume of cone = 1/3π r^2h
=1/3 * 22/7 * 5*5*12
=100*22/7
=314.28cm^2
Answered by
13
When we revolved the ∆ around the side of 12 cm , we get a cone of radii 5cm and height 12cm . Now vol. of cone =1/3π r×rh
= 1/3×22/7×5×5×12
= 22/7×5×5×4
=314.285
= 1/3×22/7×5×5×12
= 22/7×5×5×4
=314.285
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