Question

A right triangle has an area of 33 mm² and a height of 11 mm. How long is the base of the triangle? Enter your answer

Answer 1

Pls mark as brainliest answer

Answer 2

$\blue{\bold{\underline{\underline{Answer:}}}}$

$\green{\tt{\therefore{Base=6\:mm}}}$

$\orange{\bold{\underline{\underline{Step-by-step\:explanation:}}}}$

$\green {\underline \bold{Given: }} \\ \tt: \implies Area \: of \: triangle = 33 \: {mm}^{2} \\ \\ \tt: \implies Height \: of \: triangle = 11 \: {mm} \\ \\ \red{\underline \bold{To \: Find: }} \\ \tt: \implies Base \: of \: triangle = ?$

• According to given question :

$\bold{As \: we \: know \: that} \\ \tt: \implies Area \: of \: triangle = 33 \: {mm}^{2} \\ \\ \tt: \implies \frac{1}{2} \times base \times height = 33 \\ \\ \tt: \implies \frac{1}{2} \times base \times 11 = 33 \\ \\ \tt: \implies \frac{1}{2} \times base = \frac{33}{11} \\ \\ \tt: \implies base = 3 \times 2 \\ \\ \green{\tt: \implies base = 6 \: mm} \\ \\ \purple{\text{Some \: formula \: related \: to \: topic}} \\ \pink{\tt \circ \: Area \: of \: triangle = \sqrt{s(s - a)(s - b)(s - c)} } \\ \\ \pink{\tt \circ \: Area \: of \: triangle = \frac{1}{2} ab \: cos \: c}$