A right triangle has hypotenuse p cm and one side q cm .if p-q=1,find the length of the third sides.
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Let x be the length of the third side.
For a right-angled triangle, a^2+b^2=c^2
If p and q are the hypotenuse and length of the other side, then
x^2 + q^2 = p^2
thus, x^2 = p^2 - q^2
or x^2 = (p+q)*(p-q). Since a^2-b^2 = (a+b)*(a-b)
but it is given that p-q = 1. Substituting p-q=1 in the above equation, we get
x^2 = (p+q)*1 = (p+q).
Thus, x = Sqrt(p+q)
Therefore, the third side is sqrt(p+q).
For a right-angled triangle, a^2+b^2=c^2
If p and q are the hypotenuse and length of the other side, then
x^2 + q^2 = p^2
thus, x^2 = p^2 - q^2
or x^2 = (p+q)*(p-q). Since a^2-b^2 = (a+b)*(a-b)
but it is given that p-q = 1. Substituting p-q=1 in the above equation, we get
x^2 = (p+q)*1 = (p+q).
Thus, x = Sqrt(p+q)
Therefore, the third side is sqrt(p+q).
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Answer:
The third side=√(p+q)
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