Question

a right triangle having sides 6 cm 8 cm and 10 cm is revolved about the side of length 8 cm find the volume of the solid so formed

Answer 1

Clearly a cone will be formed ...The height will be 6, radius 8. Therefore volume = 1/3 × pi × r2 × h=1/3*3.14*64*6=401.9cc

Answer 2

As the triangle is revolved at 8 cm it forms a cone of height 8 cm and radius 6cm.

Volume of cone = $\frac{1}{3}$ π r² h

=$\frac{1}{3}$ * $\frac{22}{7}$ 6 * 6 * 8

=$\frac{44}{7} * 48$

=$\frac{2112}{7}$

=301.71 cm³