A rigid body is made of three idneticla tin rods in form of letter h. The body is free to rotate about fixed horizontal acis ab that passes through one of the legs of the h. The body is allowed to fall from rest from a position in which the plane of h is horizontal. What is the angular speed of the body when the plane of h is vertical.
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I knew k = 1/2 Iw^2 so I went on to find k and I about each rod and adding them together to get their total kinetic energy(potential energy)/Inertia.
When I plug this in though I get 9.60 "rad"/s. Why, what did I do wrong? After working on this problem for over an hour I (although my work doesn't show it, it took my a long time to get to this stage) I decided to us I = Icm + Mh^2, knowing that h=l, giving me a new inertia of (17M(L^2))/(12) but when plugging in I got 5.208 "rad"/s. What am I doing wrong? How do you solve this problem? Thank you for taking the time to review my question.
Hope it helps u!!
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