A rigid body of mass 6 kg is under a force which causes displacementin in it given by s= t2/4 metres where the is time the work done by the force in 2 second is
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Answered by
372
After 2s
S = t^2/4
S = 1m
v = dS/dt
v = 2t/4
v = t/2
a = dv/dt
a = 1/2 m/s^2
F = ma
F = 6*1/2
F = 3N
W = F * S
W = 3 * 1
W = 3J
S = t^2/4
S = 1m
v = dS/dt
v = 2t/4
v = t/2
a = dv/dt
a = 1/2 m/s^2
F = ma
F = 6*1/2
F = 3N
W = F * S
W = 3 * 1
W = 3J
SanskritiPandey:
Nice explanation
Answered by
79
"We can take m = 6 kg. s= t2/4 metres. After 2s, we have to consider S = t^2/4 and get the value of S is 1 m.
V = dS/dt.
v = t/2
a = dv/dt and hence we get 1/2 m/s^2
F = ma and hence we get F = 6*1/2
F = 3N
W = F * S
W = 3J
"
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