A rigid body of mass m is moving in a circle of radius r with constant speed v. The force on the body is mv2/r and is directed towards centre .What is the work done by this force in moving te body over half the circumference of the circle.
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work = Force × displacement
Force= mv^2/r
Displacement is the shortest distance between final and initial point
Shortest distance between the points in half circumference is The diameter of circle= 2r
Work=2mv^2
Force= mv^2/r
Displacement is the shortest distance between final and initial point
Shortest distance between the points in half circumference is The diameter of circle= 2r
Work=2mv^2
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