A ring of mass 100g and radius 10 cm makes 120 revolutions in one minutr about its axis find moment of inertia kinetic energy and angular momentum
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Answered by
4
Just remember that
Moment of inertia is Mr×r
KE = .5 × I × w × w
L=Iw
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m=100g=0.1kg
r=10cm =0.1m
m.o.i=m×r^2
r=10cm =0.1m
m.o.i=m×r^2
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