Area of triangle form by straight lines (4x-3y+4=0) (4x+3y-1=0) and x axis. Solution
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We have 2 equations: 4x-3y+4=0 and 4x+3y-1=0;
Formulate any 3 possible values(coordinates) for the above equation which satisfy the equations. In my case: (-1, 0) (-4, -4) and (5, 8) [for 4x-3y+4=0] and (-2,3) (1,-1) and (4, -5) [ for 4x-3y-1=0].
Now you must accordingly plot the points on the graph;
Therefore the area of the shaded region is 1.2 sq.units(approx)
Hope it helps!!! :)
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sinhaaaryan27:
Just a correction, the area is supposed to be 1 sq. units and not 1.2 as a complete unit counts in a graph enclosed figure. :)
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