Question

A ring of mass M and radius R is rotating about its axis with angular velocity omega. Two identical bodies each of mass m are now gently attached at the two ends of a diameter of the ring. Because of this, the kinetic energy loss will be :

Answer 1

Answer:

By using angular momentum conservation

MR

2

×ω=(MR

2

+MR

2

+MR

2

)ω

′

ω

′

=

M+2m

Mω

​

Loss in kinetic energy=

2

1

​

mR

2

×ω

2

−

2

1

​

(M+2m)R

2

×

(M+2m)

2

M

2

ω

2

​

=

(M+2m)

Mnω

2

R

2

​

Explanation: