Question

a river flowing steadily at a rate of 175 m3/s is considered for hydroelectric power generation. it is determined that a dam can be built to collect water and release it from an elevation difference of 80 m to generate power. determine how much power can be generated from this river water after the dam is filled.

Answer 1

Answer:

vol=175 m3/s

elevation difference = 80m

pw=1000kg/m3

g=9.81

m=pX Vol

power=w= mg.elevation difference=pw.vol.g.elevation difference=1000X175X9.81X80

=137340000W=137.34MW

Answer 2

Answer:

The power generated from the river after the dam is filled, P, calculated is $137.34\times 10^{6}W$.

Explanation:

Data given,

The flow rate of the river water, r = $175m^{3}/s$

The height of the dam to release water, h = $80m$

The power generated from the river after the dam is filled, P =?

As we know,

• Power = pressure × flow rate

And pressure = $\rho g h$

Here,

• ρ = water's density = $1000kg/m^{3}$
• g = gravity = $9.81m/s^{2}$

Therefore,

• P = $\rho g h \times rate$
• P = $1000\times 9.81\times 80\times 175$
• P = $137.34\times 10^{6}W$

Hence, the power generated from the river, P = $137.34\times 10^{6}W$.