A river of width 80m is flowing at 6 m/s. A motorboat crosses the river in 10s and reaches a point directly
across on the other river bank. The velocity of motorboat in still water is:
(9 Bms (1) 10 ms (0) 6 m/s (D) Base
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Answer: 10m/s
Explanation: since the formula for the time taken to cross the river in the minimum possible distance is :->
t = d / (Vsr^2 - Vr^2)^1/2
applying that formula we get ...
10 = 80 / (Vsr^2 - 36)^1/2
Vsr^2 - 36 = 64
Vsr^2 = 100
Vsr = 10 m/s
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