A road 10m wide surrounds a circular park whose perimeter is 352m.Find the area of the road
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Answered by
116
here's ur answer frnd!!!
circumference of the park=352m
2πr=352m
2×22/7×r=352m
44/7×r=352m
r=352/1×7/44
r=8×7
r=56m
therefore total radius along with the
road=56+10
=66m
area of the park=πr²
=22/7×56×56
=68992/7
=9856m²
area of park along with the road=πr²
=22/7×66×66
=95832/7
=13690.2857
area of the road=13690.2857-9856
=3834.2857m²
hope this helps...
circumference of the park=352m
2πr=352m
2×22/7×r=352m
44/7×r=352m
r=352/1×7/44
r=8×7
r=56m
therefore total radius along with the
road=56+10
=66m
area of the park=πr²
=22/7×56×56
=68992/7
=9856m²
area of park along with the road=πr²
=22/7×66×66
=95832/7
=13690.2857
area of the road=13690.2857-9856
=3834.2857m²
hope this helps...
ahad3:
ans hai 3834.28
Answered by
10
Answer:
Step-by-step explanation:
here's ur answer frnd!!!
circumference of the park=352m
2πr=352m
2×22/7×r=352m
44/7×r=352m
r=352/1×7/44
r=8×7
r=56m
therefore total radius along with the
road=56+10
=66m
area of the park=πr²
=22/7×56×56
=68992/7
=9856m²
area of park along with the road=πr²
=22/7×66×66
=95832/7
=13690.2857
area of the road=13690.2857-9856
=3834.2857m²
hope this helps...
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