Question

A road 7/4 km. long was prepared in 4 days. On the first day 2/5of the road, on 2nd day 1/7 of the road and on the 3rd day 5/21 of the road was repaired. What length of the road was repaired on the 4th day ?​

Answer 1

Step-by-step explanation:

First of all take the lcm of

4, 5, 7 and 21

i.e. 420

Then equalise (MAKE THE DENOMINATORS OF ALL THE FRACTIONS EQUAL) all the fractions related to it i.e.

7/4 = 735/420 (TOTAL WORK)

2/5 = 168/420

1/7 = 60 /420

5/21=100/420

Remaining work = 735 - 168 - 60 - 100

= 407

Therefore on the last day of work, the work done is

= 407/420

Hope it helped you ...............