Question

A road around a roundabout is 10m wide. If the diameter of the roundabout including the road is 24m,find the cost of levelling the road at the rate of Rs.20 per m2

Answer 1

see carefully pls
d =24 m
r1 =7m
r2 =12m
πr1^2=154
πr2^2=452.57
Area = 452.57-154=298.57m sq
Cost = 298.57 × 20 = ₹5971.4

Answer 2

The cost of levelling the road at the rate of Rs.20 per m2 is Rs.8800

Step-by-step explanation:

We are given that the diameter of the roundabout including the road is 24m

Outer diameter = 24 m

Outer radius R = $\frac{24}{2} = 12 m$

A road around a roundabout is 10 m wide.

Inner radius r = 12 m-10 m = 2 m

Area of road = Outer area - Inner area

Area of road = $\pi R^2 - \pi r^2$

Area of road =$\frac{22}{7}(12^2-2^2)$

Area of road = $440 m^2$

Cost of leveling 1 sq.m. = Rs.20

Cost of leveling 440 sq.m. = $440 \times 20=Rs.8800$

Hence the cost of levelling the road at the rate of Rs.20 per m2 is Rs.8800

#Learn more:

A circular pond is 17.5 m is of diameter. It is surrounded by a 2 m wide path. Find the cost of constructing the path at the rate of Rs 25 per m2

https://brainly.in/question/1059513