factorize 2√2x³+3√3y³
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2√2x³+3√3y³
=(√2x)³+(√3y)³
=(√2x+√3y)(2x^2+√6xy+3y^2)
=(√2x)³+(√3y)³
=(√2x+√3y)(2x^2+√6xy+3y^2)
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Step-by-step explanation:
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