Question

a road roller 140 cm long and 77 cm in diameter makes 300 revolutions to level a field completely. find area of the field. ( in metersquare )

Answer 1

The road roller is in the shape of a cylinder
radius = 77/2 cm
           =77/200 m
height = 140 cm
            =1.4 m
Curved surface area of the cylinder = 2πrh
                                                            = 2X 22/7 X 77/200 X 14/10
                                                            = 3388/1000
                                                            =3.388 m²
Area of the field = 300 X 3.388
                            = 1016.4 m²
Hope this helps.

Answer 2

Answer:

1016.4 sq.m

Step-by-step explanation:

D=77cm

C=πd

       =22/7*77

       =22*11

       =242cm

Area of Field= 140*242*300

                     = 33880*300

                     = 10,164,00sq.cm

                     = 1016.4sq.m