Question

a road roller has a diameter 0.7 m and its width is 1.2 m. find the least number of revolutions that the roller must take in order to level a polyground of size 120×44 m.​

Answer 1

Answer:

Step-by-step explanation:

Area of playground =120*44 m^2

in cylinder,

height =1.2 m

diameter =0.7 m

radius= 0.35

c. s. a =2πrh

=2*22/7*0.35*1.2

=2.64

no of revolution =area of playground/c.s.a

=120*44/2.64

=2000