a road roller makes 5000 revolutions in covering 22km.find the radius of the roller
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area covered in 5000 revolution=22km
since 1km=1000m
so,22km=22000m
Now,area covered in 1 revolution=22000/5000=
=4.4m^2
therefore c.s.a=4.4 m^2
2×pi×r×h=4.4m^2
2×22/7×r×h=4.4
44/7×r×h=4.4
r×h=4.4×7/44=0.7m
since 1km=1000m
so,22km=22000m
Now,area covered in 1 revolution=22000/5000=
=4.4m^2
therefore c.s.a=4.4 m^2
2×pi×r×h=4.4m^2
2×22/7×r×h=4.4
44/7×r×h=4.4
r×h=4.4×7/44=0.7m
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