Question

A road roller takes 1500 complete revolutions to move once over to level a road. If the radius of the roller is 21 cm and length is 50 cm, then the area of the road is equal to

Answer 1

first we find to area of surface of roller

= 2πrh

= 2×22/7×21×50

= 6600cm²

now we find area of road = 1500× 6600

= 9900000cm²

= 990m²

Answer 2

The area of road is $9900000 cm^2$

Step-by-step explanation:

Radius of roller = 21 cm

Length of roller = 50 cm

Curved surface area of cylinder = $2 \pi r h = 2 \times \frac{22}{7} \times 21 \times 50 = 6600 cm^2$

So Area covered in 1 revolution = $6600 cm^2$

Area covered in 1500 revolution = $6600 \times 1500$

Area covered in 1500 revolution = $9900000 cm^2$

Hence The area of road is $9900000 cm^2$

#Learn more :

The road roller takes 750 complete revolution to move once over to level a road find the area of the road if the diameter of road roller is84 cm and length is 1m

https://brainly.in/question/2419705