Question

A road roller takes 20 complete revolutions to move once over to level a road. Find the area of the road, if the radius of a road roller is 3.5 m and height is 2 m.

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Answer 1

Answer:

area of road = CSA of cyl. × 20

= 2πrh ×20

=2×3.17×3.5×2×20

=887.16

hope it helps u

Answer 2

≡QUESTION≡

A road roller takes 20 complete revolutions to move once over to level a road. Find the area of the road, if the radius of a road roller is 3.5 m and height is 2 m.

                                                         

║⊕ANSWER⊕║

Radius = 3.5 m

Height = 2 m

C.S.A of a cylinder

= $2\pi rh$

= $2 * \frac{22}{7} * 3.5 * 2$

= $44 m^{2}$

1 revolution = 44 m²

20 revolutions = 44 * 20

                          = 880 m²