A road roller takes 750 complete revolutions to lecel a road once. find the area of road, if the diameter is 84cm and length is 1 m.
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length = 1m
change in cm
length= 100cm
diameter=84cm
radius=diameter/2
84/2=42cm
lateral surface of road roller=2πrh
22/7*42*2*100
=26400cm sq.
total no of oscillations=750
total area =24600*750
=19800000cm sq.
change in m sq.
19800000/100*100
=1980 m sq. is the answer
hope it may help you
change in cm
length= 100cm
diameter=84cm
radius=diameter/2
84/2=42cm
lateral surface of road roller=2πrh
22/7*42*2*100
=26400cm sq.
total no of oscillations=750
total area =24600*750
=19800000cm sq.
change in m sq.
19800000/100*100
=1980 m sq. is the answer
hope it may help you
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