Math, asked by pshiwang49, 9 months ago

a road roller takes 750 complete revolutions to move once cover to level a road find the find the area of a road roller is 91 metre and length is 1.25 metre​

Answers

Answered by gopikapolajr
3

Hello :)

Length of roller = 1.25m = 125cm

Diameter of the road roller = 91m = 9100cm

Circumference of roller = π x D = 22/7 × 9100 = 28600 cm

Length of road = 28600 x 750 = 21450000 cm

Width of road = length of roller = 125 cm

Area of road = 21450000 x 125 = 2681250000hcm² or 268125 m²

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Answered by Legend42
4

Answer:

Solution:-

Given : Diameter of roller = 84 then radius = 84/2 = 42 or 0.42 m and height = 1 m

In one revolution, the road roller will cover an area equal to its lateral surface area.

So, in one revolution the area of the road covered = 2πrh

= 2*22/7*0.42*1

Area of the road in one revolution = 2.64 sq m

Therefore, in 750 revolutions, the area of the road = 2.64*750

= 1980 sq m

Answer.

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