A road roller takes 750 complete revolutions to move once over to level a good find the area of the road is the diameter of a road roller is 84cm and length is 1 m
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Solution:-
Given : Diameter of roller = 84 then radius = 84/2 = 42 or 0.42 m and height = 1 m
In one revolution, the road roller will cover an area equal to its lateral surface area.
So, in one revolution the area of the road covered = 2πrh
= 2*22/7*0.42*1
Area of the road in one revolution = 2.64 sq m
Therefore, in 750 revolutions, the area of the road = 2.64*750
= 1980 sq m
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