Question

factorise the following expression: 6-x-x²​

Answer 1

Answer:

−(x−2)(x+3).

Step-by-step explanation:

6−x−x²=−(x²+x−6)

=−(x²+3x−2x−6)

=−(x(x+3)−2(x+3))

=−(x−2)(x+3)

Hence, the answer is −(x−2)(x+3).

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Answer 2

Step-by-step explanation:

Given expression 6-x-x² rewriting it in the standard form ax²+bx+c =0

X²-x-6

X²+2x-3x-6

X(x+2)-3(x+2)

(x-3)(x+2) factors

Therefore zeroes are

(x-3)=0 ; (x+2)=0

3,-2

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