Question

a road roller takes 900 complete Revolution to move once over to level a road find the area of the road leveled if the diameter of the roller is 126 cm and its length is 2.5 metre. ​

Answer 1

The roller is cylindrical in shape,

hence one revolution of the roller = Curved surface area of the roller

C.S.A. = 2πrh where r is the radius and h is the height (or length)

r = 63 cm

h = 250 cm

C.S.A = 2×π×63×250

         = 99,000 cm²

This is the area of road leveled in one revolution

Hence area of road leveled in 900 revolutions = 99,000×900

                                                                              = 89100000 cm²

                                                                              = 8910 m²

HOPE IT HELPS !!