Question

A road runs along the four sides of a rectangular garden . length and breadth of the road are 3m and 2m resp. A man starts from one of the vertices and coveres 12m . what is the displacement of the man.
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Answer 1

perimeter of rectangular garden=2*(length+breadth)

=2*(3+2)m

=2*5m

=10m

As the man covers 12m from one of the vertices.

So, the displacement =12m-10m

=2m(ans)