Question

A road which is 7 m wide surround a circular park whose sircumference is 352 m find the area of road

Answer 1

Circumference = π × diameter
352 = 3.14d
d = 352/3.14 = 112.10m
r = d/2 = 112.10/2 = 56.05m

area = π × r²
= 3.14 × 56.05²
= 9864.6m²

D = 112.10 + 7 = 119.1m
R = D/2 = 119.1/2 = 59.55m

AREA = π×R²
= 3.14 × 59.55²
= 11135.07m²

Area of road = AREA - area
= 11135.07m² - 9864.6m²
= 1270.47m²

Answer 2

GIVEN:-

•Width of the road=7m

•Circumference of circular park=352 m

TO FIND OUT:-

$\bf \:• Area \: of \: the \: road=?$

SOLUTION:-

$\bf \:$

${\bf •Let \: the \: radius \: of \: the \: park \: be \: }r \bf \: m$

$\bf \: •Then \: its \: circumference =2 \pi r$

$\therefore \bf \: 2 \pi r=352$

$\bf \implies \: 2 \times \frac{22}{7} \times r = 352$

$\bf \implies \: r = \huge( \small352 \times \frac{7}{44} \huge) \small \: = 56$

$\bf •Thus , \: inner \: radius=56m$

$\bf \to \: outer \: radius = (56 + 7)m = 63m$

$\bf Area \: of \: road= \pi \: [(63)²-(56)²]m²$

$\bf \: \: \: \: \: \: = \frac{22}{7} \times (63 + 56)(63 - 56)m {}^{2}$

$\bf \: \: \: \: \: \implies \huge( \small \frac{22}{7} \times 119 \times 7 \huge) \small \: m {}^{2} = 2618m {}^{2}$

$\boxed{\boxed {\bf \therefore \: Required \: area \: of \: road=2618m {}^{2} }}$