Physics, asked by ashish309940, 10 months ago

A rock has a volume of 15 cm3 and a mass of 45 g. What is its density?

Answers

Answered by shivpatel123
1

Answer

Hii dear

We know that

Density = mass ÷ volume

Mass = 45g (given)

Volume = 15 cm*3 (given)

Density = 45 ÷ 15

Density = 3 g per cm*3

Answered by BrainlyConqueror0901
8

\blue{\bold{\underline{\underline{Answer:}}}}

\green{\tt{\therefore{Density=3\:g/cm^{3}}}}

\orange{\bold{\underline{\underline{Step-by-step\:explanation:}}}}

 \green{\underline \bold{Given : }}  \\  \tt: \implies Mass \: of \: rock = 45 \: g \\  \\  \tt: \implies Volume \: of \: rock = 15 \:  {cm}^{3}  \\  \\  \red{\underline \bold{To \: Find: }}  \\  \tt:  \implies Density \: of \: rock =?

• According to given question :

 \bold{As \: we \: know \: that} \\  \tt:  \implies Density =  \frac{Mass}{Volume}  \\  \\ \tt:  \implies Density =  \frac{45}{15}  \\  \\  \green{\tt:  \implies Density = 3 \: g /{cm}^{3} }\\\\  \blue {\boxed{ \bold{some \: related \: formula}}} \\  \orange{ \tt \circ \: kinetic \: energy =  \frac{1}{2}  {mv}^{2} } \\  \\ \orange{ \tt \circ \:potential \: energy =  mgh } \\  \\ \orange{ \tt \circ \: linear  \: momentum=  mv  }  \\  \\ \orange{ \tt \circ \: pressure=   \frac{force}{area} }

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