Question

A rocket is fired vertically up from the ground with an acceleration 10m/s^2. it fuel is finished after 1 min then calculate1. time taken by the rocket in the whole motion 2.max height attained by rocket

Answer 1

v = ?
u = 0
t = 60s
a = 10m/s²

Distance (Height)

s = ut + 1/2at²

s = 0 + 1/2 x 10m/s² x 3600s²

s = 0 + 5m x 3600 = 18000m

Answer 2

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հίί ʍαtε_______✯◡✯
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һєяє' ʏȏȗя ѧṅśwєя ʟȏȏҡıṅɢ ғȏя________
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✯♦The distance travelled by the rocket in 1 minute (60 s) with,

$a = 10m /{s}^{2}$
upward is ,

h1=
$\frac{1}{2} \times 10 \times {60}^{2}$

=▶18000m = 18km

♦Velocity acquired =>

v = 10 × 60

=600 m/s

♦after 1 minute the rocket moves upward with velocity 600m/s and down ward.

♦acceleration due to gravity till its velocity becomes zero

0 =
${(600)}^{2} - 2gh _{2} \:$
${(600)}^{2} - 2 \times 10 \times h _{2}$

=》
$h _{2} = 18000m$
=》
$18km$

--▶Total distance 18 +18 = 36km

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★★BRAINLY★★