Question

A rocket is launched from a platform that is 50 feet tall with an initial velocity of 120 feet per second. How high is the rocket after 2 seconds?

Answer 1

height from the point of projection..

h = ut - 0.5 g t^2 = 120 x 2 - 0.5 x 32.15 x 4

= 240 - 64.30 = 175.7 ft

height from the ground = 175.7 + 50 = 225.7 ft