Question

A rocket is launched to travel vertically upwards with a constant velocity of 20 m/s. After traveling for 35 sec the rocket develops a snag and its fuel supply is cut-off. The rocket then travels like a free body. What is the total height achieved by it? After what time of its launch will it come back to earth?​

Answer 1

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S = ut

This is because it is moving at a constant velocity.

After 35 seconds the distance will be :

S = 20 × 35 = 700m

Now from 700 m above the ground now it travels at a free fall.

The initial velocity = 20 m/s

Final velocity = 0

Acceleration due to gravity = 10

Now :

V² = U² - 2gs

0 = 400 - 20S

20s = 400

S = 400/20

S = 20 m

The total height achieved = 700 + 20 = 720 m

The time it takes to drop back to the earth is :

S = ut + 0.5gt²

u = 0

720 = 0.5 × 10 × t²

720 = 5t²

t² = 720/5

t² = 144

t = √144

= 12 seconds

The total time it takes is :

12 + 35 = 47 seconds

Answer 2

Answer:

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