Question

A rocket is moving in a gravity free space with a constant acceleration of 2ms along +x direction. The length of a chamber inside the rocket is 4 m. A ball is thrown from the left end of the
chamber in +x direction with a speed of 0.3ms relative to the rocket. At the same time, another ball is
thrown in -x direction with a speed of 0.2ms from its right end relative to the rocket. The time in
seconds when the two balls hit each other

Answer 1

Hey dear,

◆ Answer -

t = 8 s

● Explanation -

# Given -

a = 2 m/s^2

s = 4 m

v1 = 0.3 m/s

v2 = -0.2 m/s

# Solution -

As the balls are thrown at same time, acceleration of the rocket will not affect their collision.

Both balls are moving towards each other in opposite direction to cover total distance of 4 m.

s = s1 - s2

s = v1.t - v2.t

4 = 0.3 × t - (-0.2) × t

t = 4 / (0.3 + 0.2)

t = 8 s

Therefore, time taken by the balls to collide is 8 s.

Thanks for asking..

Answer 2

Answer:

t = 8 s

Explanation:

With respect of ball A (left one),

uᵣₑₗ = uA - uB = + 0.3 m/s - (- 0.2 m/s) = + 0.5 m/s

aᵣₑₗ = aA - aB = 2 - 2 = 0 (acc in a system)

xᵣₑₗ = - 4 m

We know,

xᵣₑₗ = uᵣₑₗt + 1/2aᵣₑₗt²

=> t = xᵣₑₗ/uᵣₑₗ = 4/0.5 (since t ≠ -ve)

=> t = + 8 s.