Math, asked by shaluuppalvodafon, 9 months ago

if X + Y is equal to 11 and xy is equal to 2 find the value of x square + Y square​

Answers

Answered by prajwal2612
2

Answer:

117

Step-by-step explanation:

(X+Y)^(2) = X^(2) + Y^(2) + 2XY

11^(2) = X^(2) + Y^(2) + 2×2

121 = X^(2) + Y^(2) + 4

117 =X^(2) + Y^(2)

Answered by deepsen640
42

Question:

x + y = 11

xy = 2

find the value of

x² + y²

Answer:

x² + y² = 117

Step-by-step explanation:

ACCORDING TO THE QUESTION,

given,

x + y = 11 .....(1)

xy = 2 ....(2)

from ,

equation (1)

x + y = 11

now

[Squaring of both side]

we will get,

(x + y)² = 11²

x² + y² + 2xy = 121

x² + y² = 121 - 2xy

[putting the value of xy]

x² + y² = 121 - 2(2)

x² + y² = 121 - 4

x² + y² = 117

so,

if ,

x + y = 11

xy = 2

then,

x² + y² = 117


shaluuppalvodafon: thankyou so much
shaluuppalvodafon: i will say the next question in 5 minutes
prajwal2612: ok
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