A rocket is moving up with a velocity 'v'. if the velocity is tripled, then what will be the ratio of two kinetic energies?
Explain with complete calculations & justifications.
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Answered by
609
let mass be M
original velocity = V
new velocity = 3V
original KE = 1/2 x M x V^2
New KE = 1/2 x M x(3 V)^2
ratio
= original KE / New KE
= (1/2 x M x V^2)/(1/2 x M x (3V)^2)
= V^2 / 9 V^2
=1/9
original velocity = V
new velocity = 3V
original KE = 1/2 x M x V^2
New KE = 1/2 x M x(3 V)^2
ratio
= original KE / New KE
= (1/2 x M x V^2)/(1/2 x M x (3V)^2)
= V^2 / 9 V^2
=1/9
GovindKrishnan:
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Answered by
244
Original velocity = v
Original Kinetic energy= 1/2m*v^2
New velocity =3v
New kinetic energy = 1/2m*3 v^2
ratio = 1/2mv^2/1/2m9v^2
so ratio is = 1:9
Original Kinetic energy= 1/2m*v^2
New velocity =3v
New kinetic energy = 1/2m*3 v^2
ratio = 1/2mv^2/1/2m9v^2
so ratio is = 1:9
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