Physics, asked by GovindKrishnan, 1 year ago

A rocket is moving up with a velocity 'v'. if the velocity is tripled, then what will be the ratio of two kinetic energies?

Explain with complete calculations & justifications.

Points : 10 ☺

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Answers

Answered by maria9
609
let mass be M

original velocity = V
new velocity = 3V

original KE = 1/2 x M x V^2
New KE = 1/2 x M x(3 V)^2

ratio
= original KE / New KE
= (1/2 x M x V^2)/(1/2 x M x (3V)^2)
= V^2 / 9 V^2
=1/9

GovindKrishnan: Thanks for helping! ☺
maria9: wlcm :-)
Answered by Gauravdubey1
244
Original velocity = v
Original Kinetic energy= 1/2m*v^2
New velocity =3v
New kinetic energy = 1/2m*3 v^2
ratio = 1/2mv^2/1/2m9v^2
so ratio is = 1:9

GovindKrishnan: Thanks for helping! ☺
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