A rocket is moving up with a velocity v.If the velocity of this rocket is suddenly tripled , what will be the ratio of 2 kinetic energy?
Answers
Answered by
81
Let, m be the mass of rocket.
Initial kinetic energy is, KEi = ½ mv2
Final kinetic energy is, KEf = ½ m(3v)2 = 9 KEi
Therefore, KEi : KEf = 1 : 9
Initial kinetic energy is, KEi = ½ mv2
Final kinetic energy is, KEf = ½ m(3v)2 = 9 KEi
Therefore, KEi : KEf = 1 : 9
Answered by
41
Let mass be M
original velocity = V
new velocity = 3V
original KE = 1/2 x M x V^2
New KE = 1/2 x M x(3 V)^2
ratio
= original KE / New KE
= (1/2 x M x V^2)/(1/2 x M x (3V)^2)
= V^2 / 9 V^2
=1/9
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original velocity = V
new velocity = 3V
original KE = 1/2 x M x V^2
New KE = 1/2 x M x(3 V)^2
ratio
= original KE / New KE
= (1/2 x M x V^2)/(1/2 x M x (3V)^2)
= V^2 / 9 V^2
=1/9
Hope it helps you
PLZ MARK ME AS BRAINLIEST
#BE brainly
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