Question

A rocket of mass 100 tones is moving with thrust of 5×10⁷N. Find the acceleration.​

Answer 1

Given :-

• $\sf \longrightarrow$ Mass (m) = 100 tonnes = 10000 kg = 10⁴ kg

• $\sf \longrightarrow$ Force (F) = 5 × 10⁷ N = 5 × 10⁷ kg $\sf \frac{m}{s²}$

Answer :-

• $\sf \longrightarrow \green{\bigstar} \underline{ \underline{\red{a = \frac{5 × 10³ m }{s²}}}}$

Or

• $\sf \longrightarrow \green{\bigstar} \underline{\underline{\red{a = \frac{5000 m }{s²}}}}$

Using Formula :-

• F = ma

• where,
• F = Force
• m = Mass
• a = Acceleration

Explanation :-

• $\sf \longrightarrow$ F = ma

• $\sf \longrightarrow$ 5 × 10⁷ N = 10⁴ kg × a

• $\sf \longrightarrow \frac{5 × 10⁷ \: \: N }{10⁴ \: \: kg} = a$

• $\sf \longrightarrow \frac{5 × 10 ^{7-4} \frac{kg \: m}{s²}}{kg} = a$

• $\sf \longrightarrow \frac{5 × 10 ^{7-4} \frac{\cancel{kg} \: m}{s²}}{\cancel{kg}} = a$

• $\sf \longrightarrow \frac{5 × 10³ m }{s²} = a$

• $\sf \longrightarrow \green{\bigstar} \underline{ \underline{\red{a = \frac{5 × 10³ m }{s²}}}}$

• $\sf \longrightarrow \green{\bigstar} \underline{\underline{\red{a = \frac{5000 m }{s²}}}}$

Here, SI Unit Of Acceleration = $\sf \frac{m}{s²}$

Where m = meter, s = second

I hope it helps you ❤️✔️