Question

A rocket of mass 1200kg is travelling at 2000m/s. it fires its engine for 1min. The forward thrust provided by the rocket engine is 10000N.
Use increase in momentum =f*t to calculate the increase in momentum of the rocket

Answer 1

Answer:

6,00,000 kg m/s

Explanation:

Given:

Mass = 1200 kg

Velocity = 2000 m/s

Engine fired for 1 minute

Upthrust = 10,000N

To find:

Increase in momentum

Momentum (p) = m×v

Mass (m) = 1200 kg

Velocity (v) = 2000 m/s

Momentum = 1200×2000

Momentum = 24,00,000 kg m/s

Using ΔP = F×t

F = 10,000N

Time = 60 seconds

ΔP = 10,000×60

ΔP = 6,00,000 kg m/s

The change in momentum is 6,00,000 kg m/s

we can also find the final momentum :

Final momentum = 24,00,000+6,00,000 = 30,00,000 kg m/s

The change in the momentum is equal to 6,00,000 kg m/s

Answer 2

Given :-

Mass of rocket (m)=1200 kg

Velocity = 2000m/s

Engine fired (t)= 1min = 60seconds

Upthrust [Force (f)]= 10,000N

To find

• Increase in Momentum

Momentum (p)= m×v

We have

Mass (m) = 1200kg

Velocity (v)= 2000m/s

● Momentum = m×v

p= 1200×2000

Momentum ( p) = 24,00,000kg .m/s

∆P= force × time

Force (f) = 10000N

Time (t) = 60seconds

∆P= 10,000×60

∆P= 6,00,000kg.m/s

Final momentum=24,00,000+6,00,000

=> 30,00,000kg.m/s

Increase in momentum = 60,00,000kg.m/s