Question

A rocket of mass 2030 t is launched. If a force of 30.5 MN is produced, and the burn time is 25 s, what is the speed relative to an observer at the launch point if the launch site is at a latitude of 28°N?​

Answer 1

Explanation:

F = m * (v-u)/t

u = 0

F = mv/t

v = Ft/m

v = 5 * 10^5 * 20 / (2 * 10^4)

v = 500 m/s

Velocty at the end of 20s is 500m/s

hope this helps ✌️✌️

Answer 2

Explanation:

Related answer reffer in attachment.

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