Question

find the effective resistance of resistors 0.01ohm and 107 ohms in series and parallel ​

Answer 1

Answer:

here is ur required answer

Answer 2

Answer:

107.01 and 0.0099 ohm

Explanation:

According to the given question,

R1 = 1st resistance = 0.01 ohm

R2 = 2nd resistance = 107 ohm

And we are asked to find equivalent resistance of these two resistors in series and parallel combination.

We know,

• R eq = R1 + R2 + ... + Rn

Is the formula of series combination. Where R eq is the equivalent resistance of R1, R2 ... Rn connected in series combination.

Similarly,

• 1/R' eq = 1/R1 +1/R2 + .... + 1/Rn

Is the formula of parallel combination. Where R' eq is the equivalent resistance of R1, R2, ... Rn connected in parallel combination.

Thus putting the values of our given resistance in these formulae we get,

For series combination,

• R eq = 0.01 + 107

• R eq = 107.01 ohm

For parallel combination,

• 1/R' eq = 1/0.01 + 1/107

• R' eq = 0.01×107/0.01+107

• R' eq = 1.07/107.01

• R' eq = 0.0099 ohm (approx)

Thus equivalent resistance of these two resistors connected in series and parallel combination are 107.01 ohm and 0.0099 ohm respectively.