a rocket of mass 3 into 10 power 6 Kg takes of to an altitude of 25 kilometre with the vertical velocity of 1 kilometre per second.calculate the potential and kinetic energy at the time of take off respectively.
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Answered by
202
Mass of the Rocket,m = 3×10⁶ kg
Velocity = 1 km/s = 1000 m/s
Altitude,h= 25 km = 25×1000m
=25000m
(a)Potential Energy=mgh
=3 × 10⁶ × 10 × 25000
= 75 × 10¹⁰ Joule
(b) Kinetic Energy = 1/2mv²
=1/2 × 3 × 10⁶ × (1000)²
= 1.5 × 10¹² Joule
Velocity = 1 km/s = 1000 m/s
Altitude,h= 25 km = 25×1000m
=25000m
(a)Potential Energy=mgh
=3 × 10⁶ × 10 × 25000
= 75 × 10¹⁰ Joule
(b) Kinetic Energy = 1/2mv²
=1/2 × 3 × 10⁶ × (1000)²
= 1.5 × 10¹² Joule
Answered by
73
Mass of the Rocket,m = 3×10⁶ kg
Velocity = 1 km/s = 1000 m/s
Altitude,h= 25 km = 25×1000m
=25000m
>>Potential Energy=mgh
=3 × 10⁶ × 10 × 25000
= 75 × 10¹⁰ Joule
>> Kinetic Energy = 1/2mv²
=1/2 × 3 × 10⁶ × (1000)²
= 1.5 × 10¹² Joule
HOPE IT WILL HELP YOU
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