Question

A rocket of mass 60 kg is fired in a gravity free space is ejected gaseous with velocity 300 metre per second at the rate of 2 kg per second what will be the initial acceleration of the rocket?

Answer 1

Explanation:

F=u.dm/dt

60×a=300×2kg/s

a=10m/s²

Answer 2

Given: A rocket of mass 60 kg is fired in a gravity-free space is ejected gaseous with velocity 300 metres per second at the rate of 2 kg per second

To find: Initial acceleration of the rocket

Solution: we are given v that is velocity pf the mass ejected 300m/s and mass of the rocket 60kg

dm/dt = 2kg/s

Here dm/it will be negative because the mass is decreasing with time

we know that F = vdm/dt

here F is the initial thrust force experienced by the rocket

Also, F = ma

we can say that ma = vdm/dt

putting the values in the equation

60 × a = 300 × 2

a = 10m/s^2

Therefore, the initial acceleration of the rocket will be 10m/s^2